C++ SOLUTION (Chapter 1 ) : Starting Programming



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1.      Enter 2 numbers and find the result after addition, subtraction, multiplication and division.

Soln. 
#include<iostream.h>
#include<conio.h>

void main()
{       
        clrscr();
        int i, j, add, sub, mul, div;

        cout<<"\n enter the first number";
        cin>>i;

        cout<<"\n enter the second number";
        cin>>j;

        add=i+j;
        sub=i-j;
        mul=i*j;
        div=i/j;

        cout<<"\n addition="<<add;
        cout<<"\n substraction="<<sub;
        cout<<"\n multiplication="<<mul;
        cout<<"\n division="<<div;

        getch();
}



2.      Write a program to input your age and mobile number, then print the same.

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();
        int i;
        long int j;

        cout<<"\n enter your age";
        cin>>i;
        cout<<"\n enter the phone number";
        cin>>j;
        cout<<"\name="<<i;
        cout<<"\nphone number="<<j;
        getch();
}



3.      Write a program to print a block F using hash (#), where the F has a height of six characters and width of five and four characters. 
(
Expected Output: 
                       ######
                       #
                       #
                       #####
                       #
                       #
                       #
)

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();

        cout<<"\n ######";
        cout<<"\n #";
        cout<<"\n #";
        cout<<"\n #####";
        cout<<"\n #";
        cout<<"\n #";
        cout<<"\n #";

        getch();

}



4.      Write a program to compute the perimeter and area of a rectangle with a height of 7 inches. and width of 5 inches.
(
Expected Output:
Perimeter of the rectangle = 24 inches
Area of the rectangle = 35 square inches
)

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();

        int l,b,ar,peri;
        l=7;
        b=5;

        ar=l*b;
        peri=2*(l+b);

        cout<<"\nArea="<<ar<<" Square Inches";
        cout<<"\nPerimeter="<<peri<<" Inches";

        getch();
}



5.      Write a program to compute the perimeter and area of a circle with a radius of 6 inches. 
(
Expected Output:
Perimeter of the Circle = 37.680000 inches
Area of the Circle = 113.040001 square inches
)
Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();

        float r,ar,peri;

        r=6;
        ar=3.14*r*r;
        peri=2*3.14*r;

        cout<<"\nArea="<<ar<<" square inches";
        cout<<"\nPerimeter="<<peri<<" inches";

        getch();
}



6.      Enter 2 sides of a rectangle and find the area and perimeter.

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();

        int a,b,ar,peri;

        cout<<"\n enter the length of the rectangle";
        cin>>a;

        cout<<"\n enter the breadth of the rectangle";
        cin>>b;

        ar=a*b;
        peri=2*(a+b);

        cout<<"\nArea="<<ar;
        cout<<"\nPerimeter="<<peri;

        getch();
}



7.      Write a program that takes hours and minutes as input, and calculates the total number of minutes.

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();

        int i,hr,min,tot;

        cout<<"\n enter the time in hours";
        cin>>hr;

        cout<<"\n enter the time in minutes";
        cin>>min;

        tot=(hr*60)+min;

        cout<<"\n the total number of minutes are "<<tot;

        getch();
}



 8.      Enter the length in meter and find the equivalent in centimeter and kilometer.

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{       
        clrscr();

        float m,km,cm;

        cout<<"\n enter the length in meter";
        cin>>m;

        km=m/1000;
        cm=m*100;

        cout<<"\n kilometer="<<km;
        cout<<"\n centimeter="<<cm;

        getch();
}



9.      Write a program to find the third angle of a triangle if two angles are given

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();

        int a,b,c,d;

        cout<<"\n enter the first angle";
        cin>>a;

        cout<<"\n enter the second angle";
        cin>>b;

        c=a+b;
        d=180-c;

        cout<<"\n the third angle of the triangle is"<<d;
        getch();
}




 10.  Enter the temperature in centigrade and find the equivalent in Fahrenheit.

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{       
        clrscr();
        float c,f;

        cout<<"\n enter the temperature in centigrade";
        cin>>c;

        f=( (9*c) / 5 ) + 32;

        cout<<"\ntemperature in fahrenheit="<<f;

        getch();
}


11.  Enter the radius of a circle and find the area, diameter and perimeter.

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();

        float r,ar,peri,dia;

        cout<<"\n enter the radius of circle";
        cin>>r;

        peri=2*3.14*r;
        dia=r*2;
        ar=3.14*r*r:

        cout<<"\nperimeter="<<peri;
        cout<<"\narea="<<ar;
        cout<<"\ndiameter="<<dia;

        getch();
}



Alternative Soln.

#include<iostream.h>
#include<conio.h>
#include<math.h>

void main()
{
        clrscr();
        float r,ar,peri,dia;

        cout<<"\n enter the radius of circle";
        cin>>r;

        peri=2*3.14*r;
        dia=r*2;
        ar=3.14*pow(r,2):

        cout<<"\nperimeter="<<peri;
        cout<<"\narea="<<ar;
        cout<<"\ndiameter="<<dia;

        getch();
}




 12.  Write a program that calculates the volume of a sphere. Volume of a sphere is (4/3)*Ï€ *r3

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();
        float r,volume;

        cout<<"\n enter the radius of the sphere";
        cin>>r;

        volume=(4*3.14*r*r*r)/3;
        cout<<"\nvolume="<<volume;

        getch();
}


13.  Write a program that converts kilometers per hour to miles per hour. (1km = 0.621371 miles)
(
Expected Output :
Input kilometers per hour: 15
9.320568 miles per hour
)

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();
        float km,miles;

        cout<<"\n enter the distance in kilometer per hour";
        cin>>km;

        miles=0.621371*km;

        cout<<"\n “<<miles<< “miles per hour";

        getch();
}




 14.  Write a program to read an amount (integer value) and break the amount into smallest possible number of bank notes. 

(
            e.g.
Input the amount: 485
Expected Output:
There are:

0 Note(s) of 2000.00
0 Note(s) of 500.00
2 Note(s) of 200.00
0 Note(s) of 100.00
1 Note(s) of 50.00
2 Note(s) of 20.00
0 Note(s) of 10.00
1 Note(s) of 5.00
0 Note(s) of 2.00
0 Note(s) of 1.00
)
Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();
        int i;

        cout<<"\n enter the amount";
        cin>>i;

        cout<<"\n2000 rs note : "<<i/2000;
        i=i%2000;

        cout<<"\n500 rs note : "<<i/500;
        i=i%500;

        cout<<"\n200 rs note : "<<i/200;
        i=i%200;

        cout<<"\n100 rs note : "<<i/100;
        i=i%100;

        cout<<"\n50 rs note : "<<i/50;
        i=i%50;

        cout<<"\n20 rs note : "<<i/20;
        i=i%20;

        cout<<"\n10 rs note : "<<i/10;
        i=i%10;

        cout<<"\n5 rs note : "<<i/5;
        i=i%5;

        cout<<"\n2 rs note : "<<i/2;
        i=i%2;

        cout<<"\n1 rs note : "<<i;
        getch();

}



15.  Enter a number and find the cube and square of the number.

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();
        int i,square,cube;

        cout<<"\n enter the number";
        cin>>i;

        square=i*i;
        cube=i*i*i;

        cout<<"\n square="<<square;
        cout<<"\n cube="<<cube;

        getch();
}


Alternative Soln.

#include<iostream.h>
#include<conio.h>
#include<math.h>

void main()
{
        clrscr();
        int i,square,cube;
        cout<<"\n enter the number";
        cin>>i;

        square= pow ( i,2 );
        cube= pow ( i,3 );

        cout<<"\n square="<<square;
        cout<<"\n cube="<<cube;

        getch();
}



16.  Enter a number find the double and triple of that number.

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();

        int i,d,t;

        cout<<"\n enter the number";
        cin>>i;

        d=i*2;
        t=i*3;

        cout<<"\n double of "<<i<<" = "<<d;
        cout<<"\n triple of "<<i<<" ="<<t;

        getch();
}



17.  Enter time in seconds , then show it in the Hour: Minute : Second format.
(
               e.g.
Input seconds: 25300
Expected Output:
There are:
H:M:S - 7:1:40
)

Soln.
#include<iostream.h>
#include<conio.h>

void main();
{
        clrscr();
        int i,h,m,s;

        cout<<"\n enter time in seconds";
        cin>>i;

        h=i/3600;
        i=i%3600;
        m=i/60;
        s=i%60;

        cout<<"\n H : M : S="<<h<<” : “<<m<<” : “<<s;

        getch();
}




18.   Write a program to convert a given integer (in days) to years, months and days, assumes that all months have 30 days and all years have 365 days.
Input no. of days: 2535
Expected Output:
6 Year(s)
11 Month(s)
15 Day(s).

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();

        int i,years,months,days;

        cout<<"\n enter the period of time in days";
        cin>>i;

        years=i/365;
        i=i%365;
        months=i/30;
        days=i%30;

        cout<<"years="<<years;
        cout<<"months="<<months;
        cout<<"days="<<days;
        getch();
}




 19.  Enter 2 numbers and store it into 2 variables a and b respectively. Swap the values of the variable.

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();
        int a,b,c;

        cout<<"\n enter the first number";
        cin>>a;

        cout<<"\n enter the second number";
        cin>>b;

        c=a;
        a=b;
        b=c;

        cout<<"\n swapped value of a="<<a;
        cout<<"\n swapped value of b="<<b;

        getch();
}




 20.  Enter 2 numbers and store it into 2 variables a and b respectively. Swap the values of the variable without using a third variable.

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();

        int a,b;

        cout<<"\n enter the first number";
        cin>>a;

        cout<<"\n enter the second number";
        cin>>b;

        a=a+b;
        b=a-b;
        a=a-b;

        cout<<"swapped value of a="<<a;
        cout<<"swapped value of b="<<b;

        getch();
}




21.  Enter u,t and f and then find the distance (s) using the formula s=ut+(1/2)*ft2

 Soln.
#include<iostream.h>
#include<conio.h>
#include<math.h>

void main()
{
        clrscr();
        float u,t,f,distance;

        cout<<"\n enter the value of u";
        cin>>u;

        cout<<"\n enter the value of t";
        cin>>t;

        cout<<"\n enter the value of f";
        cin>>f;

        //distance=(u*t)+(0.5*f*t*t);

        distance=(u*t)+(0.5*f*pow(t,2));
        cout<<"\n distance="<<distance;

        getch();
}




 22.  Enter 2 numbers and find the modulus without using the modulus operator (%).

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{       
        clrscr();
        int i,j,k,m;

        cout<<"\n enter the first number\n";
        cin>>i;

        cout<<"\n enter the second number\n";
        cin>>j;

        k=i / j;
        m=i – (j*k);

        cout<<"\n the modulus is"<<m;

        getch();
}



23.  Write a program to enter P, T, R and calculate Simple Interest.

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{       
        clrscr();

        int p,t,r,SI;

        cout<<"\n enter the principal";
        cin>>p;

        cout<<"\n enter the rate of interest';
        cin>>r;

        cout<<"\n enter the time";
        cin>>t;

        SI=p*r*t/100;

        cout<<"\n Simple Interest="<<SI;
        getch();
}


24.  Write a program to enter P, T, R,N and calculate Compound Interest.

Soln.
#include<iostream.h>
#include<conio.h>
#include<math.h>

void main()
{       
        clrscr();

        int p,t,r,n,CI,A;

        cout<<"\n enter the principal";
        cin>>p;

        cout<<"\n enter the  time";
        cin>>t;

        cout<<"\n enter the rate of interest";
        cin>>r;

        cout<<"\n enter the value of n";
        cin>>n;

        A=p*pow((1+r/n),(n*t));
        CI=A-p;

        cout<<"\n CI="<<CI;

        getch();
}




25.  Write a program to enter base and height of a right angled triangle and find its area.

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{       clrscr();
        float base,height,area;

        cout<<"\n enter the base of the triangle";
        cin>>base;

        cout<<"\n enter the height of the triangle";
        cin>>height;

        area=0.5*base*height;

        cout<<"\n area="<<area;
        getch();
}




 26.  Write a program to enter the coordinates (x,y) of 2 points and find the distance between those 2 points.

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();

        int x1,y1,x2,y2,dist;

        cout<<"\n enter the first coordinate of point one";
        cin>>x1;

        cout<<"\n enter the second coordinate of point two";
        cin>>y1;

        cout<<"\n enter the first coordinate of point two";
        cin>>x2;

        cout<<"\n enter the second coordinate of point two";
        cin>>y2;

        dist=pow(pow( (x1-x2) , 2) + pow( (y1-y2) , 2) , 0.5 );

        cout<<"\n Distance="<<dist;

        getch();
}




 27.  Write a program to enter two timings with hour, minute and second. Then add them and print the answer in the same format.

Soln.
#include<iostream.h>
#include<conio.h>

void main()
{
        clrscr();

        int h1,m1,s1,h2,m2,s2,h,m,s,tm,ts;

        // 1st timing

        cout<<"\n Enter the 1st timing ";
        cout<<"\n Enter hour";
        cin>>h1;
        cout<<"\n Enter minute";
        cin>>m1;
        cout<<"\n Enter second";
        cin>>s1;

        // 2nd timing

        cout<<"\n Enter the 2nd timing ";
        cout<<"\n Enter hour";
        cin>>h2;
        cout<<"\n Enter minute";
        cin>>m2;
        cout<<"\n Enter second";
        cin>>s2;

        ts = s1 + s2;
        s  = ts % 60;
        tm = m1 + m2 + (ts / 60);
        m  = tm % 60;
        h  = h1 + h2 + (tm / 60 )

        cout<<"\n total timing is "<<h<<" hours "<<m<<" minutes " << s<<"seconds";

        getch();
}





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